Raymond B. answered 08/09/23
Math, microeconomics or criminal justice
min 50x1+80x2
subject to
quadrant 1
2x1+8x2 </= 5
6x1+5x2</=10
graph them
it's a linear programming problem
test the corners of the polygon, quadrilateral, if any
for minimum you want the lower left corner (0,0)
smallest objective function is 0
solution is feasible, it's zero
max is 2650/19= 139.4736842, if that's what you really wanted, mixing up min with max