The length of a rectangle is two more than triple the width. If the perimeter is 92 inches, find the dimensions. The width is inches. The length is inches.

Answer 1

Hi Mattison!

let L = length of rectangle,

W = width of rectangle

L is two more than triple the width

Triple the width, means 3W

Two more means +2

So then,

L = 3W + 2

The Perimeter of a rectangle is

P = 2L + 2W

and we're given that P = 92in

So, you have

2L + 2W = 92

In terms of W, we know L = 3W + 2 (from above)

2(3W + 2) + 2W = 92 Substitute in for L

6W + 4 + 2W = 92 Multiply through the parentheses

8W + 4 = 92

-4 -4 Subtract 4 from both sides

---------------

8W = 88

--- --- Divide both sides by 8

8 8

W = 11in (inches is the unit of measure)

Since you know that L = 3W + 2 (from above),

see if you can find L.