Raymond B. answered 02/15/23
Math, microeconomics or criminal justice
x+y = 22/2 = 11
3x+4y = 72/2= 36
3x +3y = 33
4y-3y = y= 36-33 = 3
y=3
x = 11-3 = 8
dimensions of 1st original rectangle are 3 inches by 8 inches
Svea E.
asked 02/15/23When the length of a rectangle is x inches and the width is y inches, the perimeter is
22
inches. If the length is
tripled
and the width is
quadrupled
,
the perimeter becomes
74
inches. Find the length and width of the original rectangle.
Raymond B. answered 02/15/23
Math, microeconomics or criminal justice
x+y = 22/2 = 11
3x+4y = 72/2= 36
3x +3y = 33
4y-3y = y= 36-33 = 3
y=3
x = 11-3 = 8
dimensions of 1st original rectangle are 3 inches by 8 inches
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