Write an equation for the quadratic graphed below x-intercepts: (-2,0) and (1,0). y-intercept: (0,3)

Question

Write an equation for the quadratic graphed below

x-intercepts: (-2,0) and (1,0). y-intercept: (0,3)

Answer 1

y=-(3/2)(x+2)(x-1) in x intercept form

y=3x^2/2 +3x/2 +3 in y=ax^2+bx +c form where c=y intercept

y= -1.5)(x +1/2)^2 +3.375 in vertex form

y =a(x-h)^2 + k where (h,k) = vertex = (-1/2, 27/8) = maximum point

x intercepts -2 and 1

x coordinate of the vertex is midway between them, (-1/2, 3 3/8)

axis of symmetry is x=-1/2