Math question compound events

Question

A bowl has 2 blue candies and 3 red candies inside it.

​The tree diagram shows that the first event tells us the probability of choosing each blue and red candy.

​The second event describes the probability of choosing an additional blue and a red candy.

Answer 1

P(bbrrr)= (2/5)(1/4)=1/10

P(btbrr)=(2/5)(3/4)(1/3)=1/10

P(brrbr)=(2/5)(3/4)(2/3)(1/2)=1/10

P(brrrb)= 1/10)

P(rbbrr)=(3/5)(2/4)(1/3)=1/10

P(rbrbr)+1/10

P(rbrrb)=1/10

P(rrbbr)=1/10

P(rrbrb)=1/10

P(rrrbb)=1/10

10 outcomes, P(each)=1/10