The casts are independent, so this follows a Binomial distribution.
P(>1) = 1 - P(0)-P(1)
p = 1/6 for any die to be a 6
P(0) = (5/6)10
P(1) = 10(1/6)(5/6)9
Please consider a tutor. Take care.
Jin L.
asked 02/13/23What is the probability that in 10 casts of a fair die we get number six more than once?
Does this problem use binomial distribution? If it doesn't then what does it use? Could it be explained please?
The casts are independent, so this follows a Binomial distribution.
P(>1) = 1 - P(0)-P(1)
p = 1/6 for any die to be a 6
P(0) = (5/6)10
P(1) = 10(1/6)(5/6)9
Please consider a tutor. Take care.
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