Bradford T. answered 02/13/23
Tutor
4.9
(29)
Retired Engineer / Upper level math instructor
a) Δx = (6-3)/n = 3/n
3 is the lower bound and 3i/n is iΔx
So each right end point is 3+3i/n
b)
I ≈ ∑ni=1f(x) Δx = 3/n∑ni=1 (3+3i/n)2 = 3/n∑ni=1 (9 +18i/n + 9i2/n2)
= 27/n(n + 2(n+1)n/(2n) + n(n+1)(2n+1)/(6n2))
lim n→∞ I = 27 + 27 + 9 = 63