Maite V. answered 11/10/24
I am MS V and I promise Math with me would be FUN
This looks like a CALCULUS question
you must find the derivative of the function for x and y
set then equal to zero
then solve a system of equations
df/dx=2x-2y 2x-2y=0
df/dy=-2x+[3y2(3-3y)-y3(-3)]/(3-3y)2 all that =0 lets solve by substitution
solve for x on the first equation
2x-2y=0
2x=2y
x=y
substitute y for x on the 2nd equations -2y+[9y2-9y3+3y3 ]/(3-3y)2=0
multiply by (3-3y)2 -2y(3-3y)2 +9y2-6y3=0
square the binomial -2y(9-18y+9y2) +9y2-6y3 =0
multiply by -2y -18y+36y2-18y3+9y2-6y3=0
combine like terms and factor -24y3+45y2-18y=0
-3y(8y2-15y+6)=0
y=0 y= 15±√ 152-4*8*6 / 2*8
y=(15+3√3)/16 and y=(15-3√3)/16
since x=y x=0 x=same x=same
so the critical points are (0,0) (15+..., 15+...) and (15-...,15-...)