Find two consecutive integers such that twice the first is four more than the second

Answer 1

You can solve this by translating the given problem into symbols and then solving for x. Suppose x is the first integer. Consecutive means adding one, so the second integer is x+1. Then

2x = (x+1) + 4

2x = x+(1+4)

2x = x+5

2x + -x = x + 5 + -x (subtracting x from both sides)

(2+-1)x = (x+-x) + 5

1x = 0 + 5

x = 5

Thus the two numbers are 5 and 6.