Given the general form of a parabola x2+6x-28y+3=0, what is the x coordinate the vertex? h=_____.

Answer 1

The general form of a parabola can be written as:

x^2 + ax + by + c = 0

where (a, b, c) are constants and a, b, and c are not all zero. To find the x-coordinate of the vertex, h, we need to complete the square on the x terms. The x-coordinate of the vertex of a parabola in this form is given by:

h = -a / (2b)

In this case, a = 6, b = -28, so:

h = -a / (2b) = -6 / (-56) = 6 / 56 = 1/9.

So the x-coordinate of the vertex of the parabola is h = 1/9.