If a ball is thrown straight up into the air with an initial velocity of 90 ft/s...?

Question

if a ball is thrown straight up into the air with an initial velocity of 90 ft/s, its height in feet after t second is given by y=90(t)-16(t)squared. Find the average velocity for the time period beginning when t=1seconds of lasting.

(i) 0.5 seconds

average velocity:

(ii) 0.1 seconds

average velocity:

(iii) 0.01 seconds

average velocity:

Finally based on the above results, guess what the instantaneous velocity of the ball is when t=1

average velocity:

Answer 1