Mark M. answered 02/11/23
Retired math prof. Very extensive Precalculus tutoring experience.
rate of change = slope = (10.2 - 2.7) / (3.1 - (-1.9)) = 7.5 / 5 = 1.5
y - 10.2 = 1.5(x - 3.1)
Solve for y and plug in 115 for x.
Adara W.
asked 02/11/23The points (−1.9,2.7) and (3.1,10.2) are on the graph of a linear relationship between two variables, x and y.
1) What is the constant rate of change of y with respect to x?
2)Write a formula that expresses y in terms of x.
3)What is the value of y when x=115?
Mark M. answered 02/11/23
Retired math prof. Very extensive Precalculus tutoring experience.
rate of change = slope = (10.2 - 2.7) / (3.1 - (-1.9)) = 7.5 / 5 = 1.5
y - 10.2 = 1.5(x - 3.1)
Solve for y and plug in 115 for x.
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