Find two consecutive even integers such that eight times the smaller decreased by the larger is 40.

Question

Math

Answer 1

Let x = small even integer

Let x + 2 = larger even integer

Note that integers must differ by 2 since both are even.

8x - (x +2) = 40

8x - x - 2 = 40

7x = 42

x = 6

x + 2 = 8

Now check: Does 8 times 6 decreased by 8 = 40?

Note that we are checking the words of the problem, not the equation.The equation we wrote could be wrong!

8 times 6 minus 8 is indeed 40 so we are correct.

The 2 consecutive integers are 6 and 8.