I need help with this problem in math, please..

Question

A city planning commission recently voted to restrict the size of home remodels by limiting the floor area ratio to a maximum of 0.40 to 1. Under these guidelines,

(A) What would be the maximum allowable size of a remodel on an 11,700 sq. ft. lot??

(B) What size lot would be required in order to create a 3400 sq. ft. remodel??

Answer 1

(A) To determine the maximum allowable size of a remodel on an 11,700 sq. ft. lot, we need to first calculate the maximum allowable floor area.

To do this, we need to multiply the lot size by the maximum allowable floor area ratio of 0.40:

Maximum allowable floor area = 11,700 sq. ft. x 0.40 = 4,680 sq. ft.

Therefore, the maximum allowable size of a remodel on an 11,700 sq. ft. lot is 4,680 sq. ft.

(B) To determine the size of lot required to create a 3400 sq. ft. remodel, we need to rearrange the formula for maximum allowable floor area ratio:

Maximum allowable floor area = Lot size x maximum allowable floor area ratio

Rearranging this formula to solve for lot size, we get:

Lot size = Maximum allowable floor area / maximum allowable floor area ratio

Substituting the given values, we get:

Lot size = 3400 sq. ft. / 0.40 = 8,500 sq. ft.

Therefore, a lot size of 8,500 sq. ft. would be required to create a 3400 sq. ft. remodel under these guidelines.