Inactive Tutor answered 02/08/23
3c +2t = 25
5c +6t = 65
9c +6t = 75
5c +6t = 65
4c =10
c = 10/4 = $2.50 per chair
t = (25-3(2.5))/2 = (25-7.5)/2 = 17.5/2 = $8.75 per table
5(2.5) +6(8.75) = 12.5 + 52.50 = 65
3(2.5)+2(8.75) = 7.5 +17.5 = 25
Jared G.
asked 02/07/23A party rental company has chairs and tables to rent. There were two customers who rented both chairs and tables last week. The table shows the number of chairs, the number of tables, and the total cost in dollars for those two customers.
First customer - 3 chairs and 2 tables = 25 total
Second customer - 5 chairs and 6 tables = 65 total
How much does each chair and each table cost (in dollars) to rent?
Inactive Tutor answered 02/08/23
3c +2t = 25
5c +6t = 65
9c +6t = 75
5c +6t = 65
4c =10
c = 10/4 = $2.50 per chair
t = (25-3(2.5))/2 = (25-7.5)/2 = 17.5/2 = $8.75 per table
5(2.5) +6(8.75) = 12.5 + 52.50 = 65
3(2.5)+2(8.75) = 7.5 +17.5 = 25
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