A circle with the center at (-6, 5) and the point (3, 5) is on the circle.

Answer 1

The general form of a circle is (x - h)² + (y - k)² = r² where (h, k) is the center of the circle and "r" is the radius of that circle. We have the center, so we can plug in h = -6 and k = 5:

(x + 6)² + (y - 5)² = r²

We have a point on the circle (3. 5) which is x = 3 and y = 5 so we can plug that into our equation and solve for "r":

(3 + 6)² + (5 - 5)² = r²

9² + 0² = r²

r = 9

So, plugging that into our equation, we get: (x + 6)² + (y - 5)² = 81