Given that sin x=−2425 and x ∈ [ 3 π 2,2 π ) , find cos x . leave in a fraction

Question

Given that  sin x=−2425 sin �=−2425 and x ∈  [ 3 π 2,2 π  ) � ∈  [ 3 π 2,2 π  ) , find  cos x cos �. in fraction form for the answer

Answer 1

sinx = -0.2425, x in quadrant IV

cos^2(x) = 1- sin^2(x)= 1-(.2425)^2 = .9412

cosx = sqr(.9412) = .9702= 9702/10000= 4851/5000