Given that sin x=−2425 and x ∈ [ 3 π 2,2 π ) , find cos x . leave in a fraction

Question

Given that  sin x=−2425 sin �=−2425 and x ∈  [ 3 π 2,2 π  ) � ∈  [ 3 π 2,2 π  ) , find  cos x cos �. in fraction form for the answer

Answer 1

sinx =-.2425

cosx = sqr(1-.2425^2)=

sqr(.94119375)

= .97015

x= -14.034 degrees

cos(-14.034) = .97015