Peter R. answered 02/07/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Or W = L - 4
L * W = 165
L(L - 4) = 165
L2 - 4L - 165 = 0
(L -15)(L + 11) = 0
L = 15 (L can't be -11!)
So W = L - 4 = 15 - 4 = 11
Abi H.
asked 02/06/23the width of a rectangle is four inches less than the length. the area is 165. find the width and length
Peter R. answered 02/07/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Or W = L - 4
L * W = 165
L(L - 4) = 165
L2 - 4L - 165 = 0
(L -15)(L + 11) = 0
L = 15 (L can't be -11!)
So W = L - 4 = 15 - 4 = 11
Mark M. answered 02/07/23
Mathematics Teacher - NCLB Highly Qualified
165 = w(w + 4)
165 = w2 + 4w
0 = w2 + 4w - 165
Can you solve for w and answer?
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