please help solve this logarithm and exponential question

Question

1. Solve, rounding final answers to three decimals where appropriate, 5x/√5 = 2(6^x-2 - 2)
2. solve, rounding to 3 decimals where appropriate, log_x-4 (3x+1)=2

Answer 1

log_x-43x+1 = 2

(x-4)^2 = 3x+1

x^2 -8x +16 = 3x +1

x^2 -8x-3x +16-1 = 0

x^2 -11x +15 = 0

use the quadratic formula

x=-b/2a +/-(1/2a)sqr(b^2 -4ac)

x = 11/2 +/-(1/2)sqr(121 -60)

x = 5.5 +/-.5sqr61

x =5.5+.5sqr61 or 5.5-.5sqr61

x = about 1.595 or 9.405