Find two points on the graph of the parabola other than the vertex and x-intercepts.

Question

Consider the following function.

g(x)=(x−2)²−5

Find two points on the graph of the parabola other than the vertex and x-intercepts.

Answer 1

Hi Taylor,

To find any 2 points other than the vertex and x-intercepts, you can just plug in numbers for x.

With the form you are given, you can find that the vertex is (2, -5). So you just cannot use x=2. To make sure you don't use x-intercepts, just make sure that (x−2)²−5 ≠ 0.

So for x=0:

g(0)=(0−2)²−5 = (-2)²-5 = 4-5 = -1. The point is (0, -1).

For x=1:

g(1)=(1−2)²−5 = (-1)²-5 = 1-5 = -4. The point is (1, -4).

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