Raymond B. answered 02/18/23
Math, microeconomics or criminal justice
adult tickets sold for $9
student tickets for $3
( the - key was accidentally hit instead of the 0 key
"1-" should have read "10")
1st day 1 adult plus 10 student tickets sold for $39
2nd day 9 adult plus 8 student tickets for total $105
a+10s = 39
9a+90s=9(39)
9a +8s = 105
90s-8s = 9(39)-105
82s = 351-105
s = 246/82 = $3 for a student ticket
a = 39-10(3) = $9 for an adult ticket
9(9)+8(3)
=81+24
=$105 total ticket revenue for 9 adults and 8 students
9+10(3)
=9+30
=$39 total ticket sales for 1 adult & 10 students
2v+2b =326
11v+6b = 233
there's a mistake somewhere in the problem
as is, you get
v+b = 226/2 = 113
6v+6b = 6(113)=678
11v-6v = 233-678
5v = -445
v=-89 = negative 89 students in a van
b =113+89 = 202 students in each bus
maybe -89 means 89 ghost students?
odds are the 11 should be just 1
v+b= 113
v+6b = 233
5b = 120
b = 24 students in each bus
v = 113-24 = 89 in each van
2(89)+2(24)
= 178+48=236
89+6(24)
=89+144=233
at least there are no ghosts with 1 instead of 11 vans
althoug a bus usually carries more than a van