Raymond B. answered 02/02/23
Math, microeconomics or criminal justice
490= k/5
k = 2450
C=k/r
C= 2450/r
C= 2450/35 = 490/7 = 70 milliamperes
Current = 70 MA when resistence = 25 ohms
Ashley A.
asked 02/02/23The current in a circuit varies inversely to the resistance. If the current is 490 milliamperes (mA) when the resistance is 5 ohms, find the current when the resistance is 35 ohms.
Raymond B. answered 02/02/23
Math, microeconomics or criminal justice
490= k/5
k = 2450
C=k/r
C= 2450/r
C= 2450/35 = 490/7 = 70 milliamperes
Current = 70 MA when resistence = 25 ohms
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