passes through pts (-3,-3) find the perpendicular line to 3x+4y=-1

Answer 1

3x+4y =1

4y =-3x+1

y =-3x/4 +1/4 has slope =-3/4=coefficient of the x term when the linear equation is solved for y

the perpendicular line's slope is the negative inverse = 4/3

y =4x/3 +b, solve for b by plugging in x=-3, y=-3

-3 = 4(-3)/3 +b

b = -3+4 = 1

y = 4x/3 +1 is the perpendicular line through (-3,-3)