Michael J. answered 03/23/15
Tutor
5
(5)
Understanding all Sines of Triangles
1 = 4 (cos 45° + i sin 45)
1 = 4 (√(2) / 2 + i √(2) / 2)
1 = 2√2 + 2i √2
2 = 2 (cos 30° + i sin 30°)
2 = 2 (√(3) / 2 + i 1/2)
2 = √(3) + i
z1 * z2 =
z (2√2 + 2i√2) * z (√(3) + i)
z1 / z2 =
[z (2√2 + 2i√2)] / [z (√(3) + i)]