Since z = 1 - i |z| = sqrt( (1- i)(1+i)) = √2
With this result (1- i) = √2 exp(i θ) = √2( cos θ + i sin θ) where θ = arg z.
This is satisfied with θ = -pi/4
Obviously Re z = 1, Im z = -i
Adam L.
asked 03/23/15
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