Given the line y=2/3x-3 write the equation of a line perpendicular to it that passes through the point (4,-1)

Answer 1

The slope of the given line is 2/3. Therefore the slope any line perpendicular to this line will be -3/2 which is the negative reciprocal.

y = mx + b

-1 = (-3/2)4 + b

-1 = -6 + b

b = 5

y = (-3/2)x + 5