Peter R. answered 01/27/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
C = # chairs R = # rows
C x R = 240
If add 30 chairs, need 4 fewer rows.
(C + 30)(R - 4) = 240; C = 240/R Substitute:
((240/R) + 30)(R - 4) = 240 Use FOIL
240 +30R - 120 - 960/R = 240
30R - 120 - 960/R = 0 divide by 30;
R - 4 - 32/R = 0 mult by R to eliminate fraction;
R2 - 4R - 32 = 0 factor:
(R - 8)(R + 4) = 0 so either R = 8 or R = -4 (disregard the latter)
R = 8; C = 30 initially
Check: after revising the setup; R - 4 = 4; C + 30 = 60 4 x 60 = 240 chairs.
In retrospect, could just take the two factors of 240 that make sense in the real world for no. of rows and no. of chairs/row. 1 x 240 wouldn't work, but 3 x 80, 4 x 60, 6 x 40, 8 x 30, 10 x 24, etc. would.
Zipp S.
can i get the solution?01/27/23