A rectangular garden measures 22 ft by 27 ft . Surrounding (and bordering) the garden is a path 2 ftwide. Find the area of this path. Be sure to include the correct unit in your answer.

Answer 1

Hi Zachery, here to help!

To solve this problem, you need to draw a rectangle that's 27 ft by 22 ft (rectangle A) and then draw another rectangle around the first rectangle (rectangle B). The distance in between both rectangles is 2 ft, which is the path.

Next, we'll need to calculate the dimensions for rectangle B which has a length and width 4' longer since the path is 2 ft wide. Adding 4 ft to 27 ft by 22 ft for rectangle A will lead to 31 ft by 26 ft for rectangle B.

To calculate the area of the path, we need to subtract the area of rectangle A from rectangle B, which will be the length x width of rectangle B - length x width of rectangle A which is equal to 31x26 - 27x22, which equals 212 ft^2.

Answer 2

In order to find the area of just the pathway, you first need to find the area of the garden it self, and the total area of the garden and the pathway combined.

The area of the garden itself is the product of the length and the width.

A = W * L = 22 * 27 = 594 ft²

Then find the area of the garden and the bordering path. To do this, first find the length and width of the entire garden. Since the pathway is two feet wide, the length and width of the total garden are extended by two feet on both sides.

So, to represent the width of the total garden:

total Width = 2 + 22 + 2 = 26 ft

And to represent the length of the total garden:

total Length = 2 + 27 + 2 = 31 ft

Now find the area of the entire garden including the pathway.

total Area = W * L = 31 * 26 = 806 ft²

To find just the area of the pathway, subtract the area of the garden from the total garden including the pathway.

Path = total Area - Area of garden = 806 - 594 = 212 ft²