the sum of 3 numbers is 115 the second number is 10 less than the first and the 3rd is 3 times the second

Answer 1

F+S+T = 115

S =F-10

T = 3S= 3(F-10) = 3F-30

F + F-10 + 3F-30 = 115

5F = 115+30+10 = 155

F = 165/5 =31 = First number

S = 31-10 = 21 = Second Number

T = 3(21) = 63 = Third number

F+S+T = 31+21+63 = 115