college algebra

Question

A​ triangular-shaped deck has one side that is 6 feet longer than the shortest side and a third side that is 6 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 56 ​feet, what are the lengths of the three​ sides?

Answer 1

L = 6+s

T = 2s-6

P=56 = L+s+T

6+s +s +2s-6 = 56

4s = 56

s =56/4 = 14 feet = shortest side

L = 6+s = 20 feet = Length of another side

T =2s-6 = 28-6 = 22 feet = Third side