Write an equation for a line perpendicular to y=3x-4 and passing through the point (9,0)

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Answer 1

y=-x/3 +b perpendicular lines have negative inverse slope

the given line has slope =3=coefficient of the x term

the negative inverse of 3 is -1/3

plug in y=0, x=9 to solve for b=y intercept

0=-(9)/3 +b

b =3

y = -x/3 + 3 is the equation of the perpendicular line through the point (9,0) in slope intercept form

or

x+3y =9 in standard form