Raymond B. answered 01/22/23
Math, microeconomics or criminal justice
f(x)=x^2+4x-12
f(g(x))= x^2-10x+9
let g(x)=ax+b, solve for a and b
f(ax+b)= (ax+b)^2 +4(ax+b) -12
= a^2x^2 +2abx +b^2 +4ax+4b-12=x^2-10x +9
set coefficients on left and right sides equal
a=1 for x^2
2ab+4a=-10=2(1)b+4(1) for x
2b=-14
b= -7
g(x)= ax+b=(1)x-7
g(x)=x-7
check the answer
b^2+4b-12=9 for the constant term
49-28-12 =9
9=9
f(g(x)=f(x-7)= (x-7)^2+4(x-7)-12
= x^2-14x+49 +4x-28 -12
= x^2 -10x +9