Write the equation of a line that is perpendicular to y=-x-6y that passes through the point (-9,-4)

Question

Write the equation of a line that is perpendicular to y=-x-6y=−x−6y, equals, minus, x, minus, 6 and that passes through the point (-9,-4)(−9,−4)left parenthesis, minus, 9, comma, minus, 4, right parenthesis.

Answer 1

I believe you have an extra y in your equation.

y=-x-6

Perpendicular means the slope changes:

m2 = -1/m1

The slope in your original equation is -1.

The slope of the perpendicular line is -1/(-1)= 1

Your new line's equation is now y=x+b.

You can find b by substituting in your given point (-9,-4).

-4=-9+b

b=5

y=x+5

Answer 2

Hi Kylie W

Line

y = - x - 6

Is in Slope Intercept Form of

y = mx + b

m, the slope is -1

A perpendicular line would have a slope that is the inverse of negative 1 with an opposite sign so

m = -(1/-1) = 1 or just positive 1

Your perpendicular line starts as

y = x + b

We can use the coordinates of the points given to calculate b

-4 = -9 + b

-4 + 9 = b

5 = b

Finally

y = x + 5

To confirm that it is perpendicular to y = -x - 6 and passes through (-9, -4) graph it at Desmos.com on the same grid.

You can also graph them by hand.

https://www.desmos.com/calculator/cvwnfzut10