Isabella F.
asked 01/21/23Equations by Substitution Alg.1
Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of
14
people took the trip. She was able to purchase coach tickets for
$230
and first class tickets for
$1030.
She used her total budget for airfare for the trip, which was
$9620.
How many first class tickets did she buy? How many coach tickets did she buy?
1 Expert Answer
Peter R. answered 01/21/23
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Re: no. of people: C + F = 14 (F = 14 - C)
Coach costs $230; 1st Class (F) costs $1030.
Total cost: 230C + 1030(14 - C) = 9620
230C + 14420 - 1030C = 9620
-800C = -4800
C = 6; F = 8
Check: 6($230) + 8($1030) = $1380 + $8240 = $9620
Isabella F.
Thank you Peter!01/21/23
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Junel L.
There are 14 people to consider for the tickets, all in all costs $9620 with the price of $230 each for coach tickets and $1030 each for first class tickets. Consider X = no. of people in coach tickets and Y = no. of people in first class tickets. Since = X + Y, then we have X= 14 - Y. Now, $9620 = $230(X) + $1030(Y), $9620 = $230(14 - Y) + $1030(Y) => $9620 = $3220 - $230Y + $1030Y => $6400= $800Y => 8=Y. Hence, we have 14 = X + Y => 14 = X + (8) => 14 - 8 = X => 4 =X. Therefore, there are 4 tickets for coach tickets and 8 tickets for first class tickets purchased amounting to $9620.01/27/23