Raymond B. answered 01/17/23
Math, microeconomics or criminal justice
y=k/sqr(x)
x=KT^3
y=k/sqr(KT^3)= k/sqrK(sqrT^3)
8= k/sqrK(sqr(25)^3)
k/sqrK = 5(8)(sqt5)= 40sqr5
y= (40sqr5)/sqrT^3
sqrT^3= (40sqr5)/27
square both sides
T^3= (1600)(5)/27^2=8,000/729= (20/9)^3
take the cube root of both sides
T= 20/9 = 2 2/9 = 2.222...
T=20/9 when y=27
check the answer
x=K(20/9)^3= 8000K/729
27= k/sqrx = k/sqr(8000K/729)
=(k/K)/sqr(8000/729)=40sqr5/(20/9)(sqr(20/9)
=18sqr5/(2/3)sqr5=18(3/2)=27