Raymond B. answered 01/12/23
Math, microeconomics or criminal justice
y=0
x^2 + y^2 = 4
x^2 + 0 = 4
x =+/-sqr4 = + or -2
4 + y^2 = 4
y^2 = 0
y = 0
solutions are (-2,0) and (2,0)
graphically the quadratic is a circle with center at the origin and radius = 2
the linear equation is a flat horizontal line = the x axis, which cuts the circle in half
intersecting the circle at its right and left sides
30^2 = 900
(x-y)^2 = x^2 -2xy +y^2 = (35-5)^2 = 35^2 -2(35)(5) + 5^2
= 1225 -350 +25 = 1250-700 = 900
9^2 +10^2 = 729+1000 = 1729
=(a+b)(a^2 -ab + b^2)
= (9+10)(9^2 -9(10) + 10^2)
= 19(81 -90 +100)
= 19(91)= 1729