Simon has $2.12 in pennies, nickels, dimes, and quarters. How many of each coin could Simon have

Answer 1

p+5n+10d +25q = 212

many possibilities:

8 quarters 1 dime 2 pennies

7 quarters, 3 dimes, 1 nickel, 2 pennies

7 quarters, 3 dimes, 7 pennies

7 quarters, 2 dimes, 3 nickels, 2 pennies

7 quarters 2 dimes, 2 nickels, 7 pennies

7 quarters 2 dimes, 1 nickel 12 pennies

7 quarters, 2 dimes, 17 pennies

7 quarters 1 dime 5 nickels 2 pennies

7 quarters, 1 dime, 4 nickels, 7 pennies

7 quarters 1 dime, 3 nickels, 12 pennies

7 quarters, 1 dime, 2 nickels, 17 pennies

7 quarters, 1 dime 1 nickel 22 pennies

7 quarters, 1 dime 27 pennies

....

etc.

...

212 pennies