What is an equation of the line that passes through the point (1,7) and is perpendicular to the line x+6y=42

Answer 1

First I’d put the equation into standard form so x+6y=42 is the same as y = (-1/6)x + 7. The perpendicular slope to this line is the negative reciprocal of the slope of the original line which is (-1/6). Thus the perpendicular slope is 6. Now we need a line that has slope of 6 and passes through the point (1,7). We can use point slope form yielding:

y-7= 6(x-1) or putting into standard form y = 6x+1.

Answer 2

Determine the slope of x + 6y = 42, call it m

Determine the number -1 / m, this is slope of perpendicular

Use solpe of perpendiculat and point in point-slope form