Raymond B. answered 01/16/23
Math, microeconomics or criminal justice
2x^2 +11x +12 = Area = Length times Width
= (2x+3)(x+4) = Length times Width
possible dimensions: 3 by 4, 5 by 5, 11 by 6
for x = 0, 1 or 2
Length = 2x+3, Width = x+4
x>-4 and x>-3/2 to keep the dimensions >0
Area >0
double Width, increase Length by 2
L=2x+3+2 = 2x+5
W=2(x+4) = 2x+8
Area = A = (2x+5)(2x+8) = 4x^2 +26x +40
A= 4x^2 +26x +40
x>-3/2
new Area > 4(3/2)^2 -26(3/2)+40 = 9-39+40=10
new Area >10
possible dimensions: 5 by 8, 7 by 10, 9 by 12
if x=0,1 or 2