Write an equation for the line that passes through (-8,-10) and is parallel to the line whose equation is y= -4x+3

Answer 1

Use point-slope form

y + 10 = -4(x + 8)

Answer 2

As the desired line is parallel to the line with equation y = -4x + 3, the desired line will have a slope of -4. Thus, our desired line has the equation y= -4x + b, where b is a constant.

Plugging in our point (-8,-10) into the equation above, where x= -8 and y= -10, we get -10 = -4(-8) + b, so we have -10 = 32 + b. Rearranging to solve for b, we get b = -42. Thus, our desired line has equation y = -4x - 42.