x= 4√2 y= 4√2 z= ?

Question

please help! I've been stuck here for a good 30mins. Its Pythagorean theorem

Answer 1

z = sqrt(x² + y²)

x² = (4 sqrt(2))² = 4²(sqrt(2))² = 16(2) = 32

z = sqrt(32 + 32) = 8 (+/- 8 in algebra class)

Please consider a tutor. Take care.

Answer 2

x= 4√2 y= 4√2 z= ?

PYTHAGOREAN THEOREM

SIDE² + SIDE² = HYP²

X^{2 +} y² = z²

(4√2)² + (4√2)² = z²

(16)(2) + (16)(2) = z²

32 + 32 = z²

64 = z²

√64 = √z²

8 = z

z = 8

SHORTCUT -- ISOSCELES TRIANGLE [both short sides = 4√2]

MULTIPLY short side by √2 to calculate hypotenuse [longest side]

√2 x = z

√2 (4√2) = z

2 (4) = z

8 = z



z = 8

SHORTCUT EXPLANATION -- √2 (√2) = √4 = 2

THEN MULTIPLY 2 by 4 = 8