A line with a slope of –1/10 passes through the point (10, –1). What is its equation in slope-intercept form?

Answer 1

If you are familiar with point-slope form as shown in the other answer, that is a great way to answer questions like these! However, in case you're not as familiar with that form, here's a way to use a familiar slope-intercept form (y = mx + b) to answer this question.

Remember that in the equation y = mx + b, m represents the slope of the line and b represents the y-intercept of the line.

You're already told that the slope is -1/10, so we can substitute that into the equation directly, and now we have y = -1/10 x + b.

We will use the given point (10, -1) to figure out the rest of the equation. We will substitute this coordinate in the (x, y) of the equation:

-1 = -1/10 (10) + b

-1 = -1 + b

0 = b

So our equation is y = -1/10 x + 0 or more simply y = -1/10 x.

This means that this line has a slope of -1/10 and goes through the origin (0, 0).

Answer 2

y +1 = (-1/10)(x-10) in point slope form

y= -x/10 +1 -1

y = -x/10 in slope intercept form, with slope =-1/10 and y intercept =0

or more explicitly

y = (-1/10)x + 0