What is an equation of the line that passes through the points (4, -2) and (6,1)

Answer 1

Hi,

points (4, -2) and (6,1)

First, find slope

slope = (-2-1)/(4-6) = -3/-2 = 3/2

Second, write equation of line as slope form: y = mx + b ===> y = 3/2 x + b #1

Third, for finding b, choose one of given points and replace to the equation #1

so I chose (6,1) then 1 = 3/2 (6) + b ====> b = -8

Result: equation of line through of given points is y = 3/2 x - 8

I hope it is useful.

Minoo

Answer 2

The two points are (4, -2) and (6,1) Use point-slope form: y₂ - y₁ = m(x₂ - x₁)

First find slope m: rise/run = Δy/Δx = [1 - (-2)]/(6 - 4) = 3/2

Then, using (6,1) as the reference point: y - 1 = 3/2(x - 6) Use distributive rule to eliminate the parentheses.

y - 1 = (3/2)x - 9

y = (3/2)x - 8 in slope-intercept form.

Check it on the Desmos Graphing Calculator website.