Raymond B. answered 12/19/22
Math, microeconomics or criminal justice
let x = amount invested at 11%
14800-x = amount invested at 2%
.11x -.02(14,800-x) =211
.11x+.02x = 211+.02(14,800)
.13x = 211 +296= 507
x= 507/.13=$3900 invested at 11%
14800-3900= $10,900 invested at 2%
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check the answers:
.11(3900)-.02(10900)
=429-218
=211