Find an equation perpendicular to y=-3x-5 and passing through (7,3)

Question

Perpendicular to y=-3x-5 and passing through (7,3)

Answer 1

y-3 = (1/3)(x-7) is the perpendicular line through the given point, in point slope form

x-3y = -2 in standard form

y = x/3 + 2/3 in slope intercept form. slope = 1/3, intercept = 2/3

x-3y +2 = 0 in general form

perpendicular line's slope = negative inverse of -3/1 = - -1/3 = +1/3

change the sign and flip it upside down

slope = the coefficient of the x term when a linear equation is solved for y

ignore the -5 constant term in the original equation, it's irrelevent to this problem