The vertices of a triangle are A(-1,2),B(-4,-2) and C(2,-1).Find the perimeter of the triangle correct to 1 decimal place.

Answer 1

(-1,2), (-4,-2) and (2,-1) are a triangle's vertices

the perimeter is the sum of AB +AC+BC

= 5+3sq2 + sqr37

= about 5+4.242 + 6.083

= about 15.325

= about 15.3

use the Pythagorean Theorem to calculate AB, AC and BD, then sum them