what is an equation of a line perpendicular to 2x-2y=-6 that passes through the point (9,6)

Answer 1

2x-2y=-6

divide by 2

x-y=-3

y=x+3 has slope =1, any perpendicular line has the negative inverse slope = -1

y=-x + b is a perpendicular line. to solve for b, plug in the point (9,6) x=9, y=6

6=-9+b

b=9+6

b = 15

y=-x+15 is the perpendicular line through the given point, in slope intercept form

or

x+y =15 in standard form

or

x+y-15=0 in general form ax+by+c=0 a=b=1, c=-15

or

y-6 = (-1)(x-9) in point slope form

y-6=-x-9