find the equation of a line perpendicular to 2x-2y=-6 that passes through the point (9,6)

Answer 1

x+y=15 is the perpendicular line through (9,6)

9+6=15

2x-2y=-6, solve for y

y = -2x/-2 -6/-2

y = x +3 the coefficient of x = the slope = 1

the perpendicular line has slope = the negative inverse of 1 which =-1

the perpendicular line is y=(-1)x + b where b= the y intercept. find b by plugging in the point (9,6)

6=-9+b

b =15

y=-x+15 is the perpendicular line in slope intercept form

or

x+y=15 in standard form