What is h'(2) if h(x) = g(2+f(x^2-1))

Question

Answer 1

Hi Ryc,

This is a chain rule question.

h'(x) = g'(2+f(x^2-1))*(0+f'(x^2-1))*2x

h'(2) = g'(2+f(3))*(f'(3))*4

f(3) = 3, so

h'(2) = g'(2+3)*f'(3)*4

h'(2) = g'(5)*f'(3)*4

f'(3) = 2, so

h'(2) = g'(5)*2*4

= 8*g'(5)

I don't see what g'(5) is in your table. Is there a missing row?